请教一个 jQuery 调用 Json 问题。

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{
"resultcode": "200",
"reason": "成功的返回",
"result": {
"company": "顺丰",
"com": "sf",
"no": "594841046352",
"list": [{
"datetime": "2015-03-29 18:42",
"remark": "顺丰速运已收取快件",
"zone": ""
}, {
"datetime": "2015-03-29 19:09",
"remark": "快件在武汉建一服务点, 正转运至武汉吴家山集散中心",
"zone": ""
}, {
"datetime": "2015-03-29 20:16",
"remark": "快件到达武汉吴家山集散中心",
"zone": ""
}, {
"datetime": "2015-03-29 21:51",
"remark": "快件在武汉吴家山集散中心, 正转运至武汉东西湖集散中心2",
"zone": ""
}, {
"datetime": "2015-03-29 22:51",
"remark": "快件在武汉东西湖集散中心2, 正转运至上海虹桥集散中心",
"zone": ""
}, {
"datetime": "2015-03-30 12:28",
"remark": "快件到达上海虹桥集散中心2",
"zone": ""
}, {
"datetime": "2015-03-30 12:47",
"remark": "快件在上海虹桥集散中心2, 正转运至上海长风服务点",
"zone": ""
}, {
"datetime": "2015-03-30 13:29",
"remark": "快件到达上海长风服务点",
"zone": ""
}, {
"datetime": "2015-03-30 13:31",
"remark": "正在派送途中,请您准备签收(派件人:衡中林,电话:18301891806)",
"zone": ""
}, {
"datetime": "2015-03-30 19:51",
"remark": "快件派送不成功(因暂无法联系到收方客户),正在处理中,待再次派送",
"zone": ""
}, {
"datetime": "2015-03-31 08:16",
"remark": "正在派送途中,请您准备签收(派件人:衡中林,电话:18301891806)",
"zone": ""
}, {
"datetime": "2015-03-31 10:12",
"remark": "已签收,感谢使用顺丰,期待再次为您服务",
"zone": ""
}, {
"datetime": "2015-03-31 10:12",
"remark": "在官网\"运单资料&签收图\",可查看签收人信息",
"zone": ""
}],
"status": 1
},
"error_code": 0
}

请问这样的层级关系，我想调用 list 层，并且循环，我该如何操作呢？

company com no 我都会。。。

本人 JS 好差。。

remark

datetime

快件

11 replies • 2015-04-09 19:31:00 +08:00

ALeo

Apr 9, 2015

data.list.each

tension

Apr 9, 2015

@ALeo

我现在写的
$.each(value.result.list,function(i,n){
html +='<dd>';
html +=''+datetime+''+remark+'';
html +='</dd>';
});

不对么？

ALeo

Apr 9, 2015

@tension 肯定不对。。

$.each(value.result.list,function(val){
html +='<dd>';
html +=''+val.datetime+''+val.remark+'';
html +='</dd>';
});

tension

Apr 9, 2015

@ALeo 还是不行，获取不到值啊？

subpo

Apr 9, 2015

list.forEach(function(item){
console.log(item)
})

tension

Apr 9, 2015

@ALeo 获取出来的行数对了，但是内容显示 undefined

tension

Apr 9, 2015

var info = data.result.list;
var html = "";
$.each(info,function(val){
html +='<dd>';
html +=''+val.datetime+''+val.remark+'';
html +='</dd>';
});

tension

Apr 9, 2015

@ALeo

var info = data.result.list;
var html = "";
$.each(info,function(n,val){
html +='<dd>';
html +=''+val.datetime+''+val.remark+'';
html +='</dd>';
});

搞定

xmbaozi

Apr 9, 2015

tension

Apr 9, 2015

@xmbaozi 正在考虑是否想把整站搞成整站模版的

qiuai

PRO

Apr 9, 2015

@tension 你还要脸的话,赶紧联系我.要么还钱,要么把货发出来.
没你这么办事的.