Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
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class Solution {
public:
int singleNumber(vector<int>& nums) {
int ret = 0;
for(int i:nums) {
ret ^= i;
}
return ret;
}
};
上 leetcode 做了一道题,怎么也想不明白为什么这个写法效率这么低,效率最高的那部分代码要怎么写才能达到?