Laravel5 中应如何使用 try{}catch(){}捕获 Eloquent ORM 的异常？

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比如：

try{
  $user = \App\User::find(1);
  $user->email = $email;
  $user->save();
  return response()->json([ 'msg' => 'success']);
}catch( ??? ){
  return response()->json([ 'msg' => 'error','d' => 捕获到的异常信息 ]);
}

我应如何写才能捕获到异常？

捕获

user-

JSON

msg'

8 replies • 2016-07-19 23:53:28 +08:00

ZGLHHH

Jul 19, 2016

通过 Google 找到了答案：
https://laracasts.com/discuss/channels/eloquent/eloquent-trycatch-on-duplicate-key-exception-and-delete
https://laracasts.com/discuss/channels/general-discussion/how-to-catch-queryexception
https://laravel.com/api/5.1/Illuminate/Database/QueryException.html

yangqi

Jul 19, 2016

你这最常见的应该是 ModelNotFoundException

https://laracasts.com/discuss/channels/tips/a-list-of-most-common-laravel-errors-exceptions

yangqi

Jul 19, 2016

@ZGLHHH QueryException 是通用 exception, 应该放到全局的 exception handler 里面。不然你每执行一次 query 都要 catch 然后 handle 一遍不是要累死。。。

ZGLHHH

Jul 19, 2016

@yangqi 那么请问应如何全局 exception handler ？

yangqi

Jul 19, 2016

app/Exceptions/Handler.php

https://laravel.com/docs/5.2/errors#the-exception-handler

ZGLHHH

Jul 19, 2016

@yangqi 那么就是把 catch()括号里的这部分挂载到 App\Exceptions\Handler 吗？
catch(\App\Exceptions\Handler $e){
}

yangqi

Jul 19, 2016

@ZGLHHH 不是，官方文档写的很清楚

ZGLHHH

Jul 19, 2016

@yangqi 这是个全局的异常处理器，但是我有几个函数需要另一种异常处理。
难道要在 handler 里写判断是哪种异常决定返回什么吗？